What is (\partial)/(\partial z)(yze^x) ?

The answer to (\partial)/(\partial z)(yze^x) is e^xy

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(\partial)/(\partial z)(yze^x)

\frac{\partial}{\partial z} (yz e^{x})

e^{x} y

Solution steps

\frac{\partial}{\partial z} (yz e^{x})

Treat

y, x

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y e^{x} \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= y e^{x} \cdot 1

Simplify

= e^{x} y

\frac{\partial}{\partial x} (x e^{- x^{2} - y^{2} - z^{2}})

\int 4 sin (2 θ) d θ

\int_{- 2}^{2} x^{2} - 4 d x

\frac{d}{d x} (3 sin^{2} (x) + sec (2 x))

f (x) = x + \frac{1}{x}, at x = 4

What is (\partial)/(\partial z)(yze^x) ?
The answer to (\partial)/(\partial z)(yze^x) is e^xy