What is taylor x^4+2x,1 ?

The answer to taylor x^4+2x,1 is 3+6(x-1)+6(x-1)^2+4(x-1)^3+(x-1)^4

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taylor x^4+2x,1

taylor

x^{4} + 2 x, 1

3 + 6 (x - 1) + 6 (x - 1)^{2} + 4 (x - 1)^{3} + (x - 1)^{4}

Solution steps

Apply the Taylor Formula

= 3 + \frac{\frac{d}{d x} ( x ^{4} + 2 x ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{4} + 2 x ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{4} + 2 x ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 3 + \frac{6}{1 !} (x - 1) + \frac{12}{2 !} (x - 1)^{2} + \frac{24}{3 !} (x - 1)^{3} + \frac{24}{4 !} (x - 1)^{4}

Refine

= 3 + 6 (x - 1) + 6 (x - 1)^{2} + 4 (x - 1)^{3} + (x - 1)^{4}

(12 x + x^{2} + 0.05 x^{3})^{^{'}}

\int_{- 1}^{1} e^{y} - (y^{2} - 2) d y

n = 2 \sum \infty \frac{3}{4 ^{n}}

\frac{\partial}{\partial x} (cos^{7} (x^{4} y^{6}))

\frac{\partial}{\partial x} (ln (1 + x^{2} + y^{2}))

What is taylor x^4+2x,1 ?
The answer to taylor x^4+2x,1 is 3+6(x-1)+6(x-1)^2+4(x-1)^3+(x-1)^4