What is area f(x)=2x^2+2,[-2,3] ?

The answer to area f(x)=2x^2+2,[-2,3] is 100/3

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area f(x)=2x^2+2,[-2,3]

area

f (x) = 2 x^{2} + 2, [- 2, 3]

\frac{100}{3}

Decimal

33.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} 2 x^{2} + 2 d x

Solve

\int_{- 2}^{3} 2 x^{2} + 2 d x : \frac{100}{3}

The area is:

= \frac{100}{3}

\int \frac{1}{x ^{2} 4 + x ^{2}} d x

\int \frac{e ^{x}}{e ^{2 x} - 3 e ^{x} + 2} d x

\frac{d}{d x} (tan^{2} (3 x) + 1)

\int t^{2} e^{- \frac{t}{3}} d t

n = 7 \sum \infty \frac{1}{6 n}

What is area f(x)=2x^2+2,[-2,3] ?
The answer to area f(x)=2x^2+2,[-2,3] is 100/3