What is (\partial)/(\partial x)(x+y-xy) ?

The answer to (\partial)/(\partial x)(x+y-xy) is -y+1

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(\partial)/(\partial x)(x+y-xy)

\frac{\partial}{\partial x} (x + y - x y)

- y + 1

Solution steps

\frac{\partial}{\partial x} (x + y - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x y) = y

= 1 + 0 - y

Simplify

= - y + 1

\int_{0}^{8} (x + 1)^{2} d x

y = arcsin (\frac{1}{x ^{5}})

x \to 0 lim (\frac{ln ( 1 - 6 x )}{x})

x \to - 8 lim (\frac{∣ x + 8 ∣}{x + 8})

- \frac{4 x}{y}

What is (\partial)/(\partial x)(x+y-xy) ?
The answer to (\partial)/(\partial x)(x+y-xy) is -y+1