What is the derivative of f(x)=x^3-6x+9 ?

The derivative of f(x)=x^3-6x+9 is 3x^2-6

What is the first derivative of f(x)=x^3-6x+9 ?

The first derivative of f(x)=x^3-6x+9 is 3x^2-6

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derivative of

f (x) = x^{3} - 6 x + 9

3 x^{2} - 6

Solution steps

\frac{d}{d x} (x^{3} - 6 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (9) = 0

= 3 x^{2} - 6 + 0

Simplify

= 3 x^{2} - 6

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What is the derivative of f(x)=x^3-6x+9 ?
The derivative of f(x)=x^3-6x+9 is 3x^2-6
What is the first derivative of f(x)=x^3-6x+9 ?
The first derivative of f(x)=x^3-6x+9 is 3x^2-6