What is the derivative of ln(3)+e^{x^e} ?

The derivative of ln(3)+e^{x^e} is e^{x^e+1}x^{e-1}

What is the first derivative of ln(3)+e^{x^e} ?

The first derivative of ln(3)+e^{x^e} is e^{x^e+1}x^{e-1}

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derivative of

ln (3) + e^{x^{e}}

e^{x^{e} + 1} x^{e - 1}

Solution steps

\frac{d}{d x} (ln (3) + e^{x^{e}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (3)) + \frac{d}{d x} (e^{x^{e}})

\frac{d}{d x} (ln (3)) = 0

\frac{d}{d x} (e^{x^{e}}) = e^{x^{e} + 1} x^{e - 1}

= 0 + e^{x^{e} + 1} x^{e - 1}

Simplify

= e^{x^{e} + 1} x^{e - 1}

y^{^{''}} - 5 y^{^{'}} = 10 x + 3

x y y^{^{'}} + x^{2} + y^{2} = 0

\int \frac{5 x ^{4} + 6}{x ^{5} + 6 x} d x

x \to 5 + lim (\frac{4}{x - 5})

x \to 0 lim (x^{8} - \frac{1}{x})

What is the derivative of ln(3)+e^{x^e} ?
The derivative of ln(3)+e^{x^e} is e^{x^e+1}x^{e-1}
What is the first derivative of ln(3)+e^{x^e} ?
The first derivative of ln(3)+e^{x^e} is e^{x^e+1}x^{e-1}