What is the derivative of (x^2+2x/(1-x^2)) ?

The derivative of (x^2+2x/(1-x^2)) is (2x^2+2x+2)/((1-x^2)^2)

What is the first derivative of (x^2+2x/(1-x^2)) ?

The first derivative of (x^2+2x/(1-x^2)) is (2x^2+2x+2)/((1-x^2)^2)

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\frac{d}{d x} (\frac{x ^{2} + 2 x}{1 - x ^{2}})

\frac{2 x ^{2} + 2 x + 2}{( 1 - x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 2 x}{1 - x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} + 2 x ) ( 1 - x ^{2} ) - \frac{d}{d x} ( 1 - x ^{2} ) ( x ^{2} + 2 x )}{( 1 - x ^{2} ) ^{2}}

\frac{d}{d x} (x^{2} + 2 x) = 2 x + 2

\frac{d}{d x} (1 - x^{2}) = - 2 x

= \frac{( 2 x + 2 ) ( 1 - x ^{2} ) - ( - 2 x ) ( x ^{2} + 2 x )}{( 1 - x ^{2} ) ^{2}}

Simplify

\frac{( 2 x + 2 ) ( 1 - x ^{2} ) - ( - 2 x ) ( x ^{2} + 2 x )}{( 1 - x ^{2} ) ^{2}} : \frac{2 x ^{2} + 2 x + 2}{( 1 - x ^{2} ) ^{2}}

= \frac{2 x ^{2} + 2 x + 2}{( 1 - x ^{2} ) ^{2}}

x^{4} + 6 x^{2} - x

\int \frac{sin ( y )}{cos ( y )} d y

\frac{\partial}{\partial y} (- e^{- x} sin (y))

\frac{\partial}{\partial y} (4 x^{2} + 4 x y - 3 y^{2} + 4 y - 1)

x \to 1 lim (x - 1)

What is the derivative of (x^2+2x/(1-x^2)) ?
The derivative of (x^2+2x/(1-x^2)) is (2x^2+2x+2)/((1-x^2)^2)
What is the first derivative of (x^2+2x/(1-x^2)) ?
The first derivative of (x^2+2x/(1-x^2)) is (2x^2+2x+2)/((1-x^2)^2)