What is area 4cos(7x),4-4cos(7x),0, pi/7 ?

The answer to area 4cos(7x),4-4cos(7x),0, pi/7 is (4pi+24sqrt(3))/(21)

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area 4cos(7x),4-4cos(7x),0, pi/7

area

4 cos (7 x), 4 - 4 cos (7 x), 0, \frac{π}{7}

\frac{4 π + 24 3}{21}

Decimal

2.57788 \dots

Solution steps

Apply the area formula:

\int_{0}^{\frac{π}{7}} ∣ 4 cos (7 x) - (4 - 4 cos (7 x)) ∣ d x

Solve

\int_{0}^{\frac{π}{7}} ∣ 4 cos (7 x) - (4 - 4 cos (7 x)) ∣ d x : \frac{4 π + 24 3}{21}

The area is:

= \frac{4 π + 24 3}{21}

\frac{( s + 1 )}{s ^{2} + 1}

\frac{9}{x}

x \to 0 - lim (3^{\frac{1}{x}})

\int \frac{x ^{2}}{x x ^{2} - x + 1} d x

\int x cos (\frac{1}{2} x) d x

What is area 4cos(7x),4-4cos(7x),0, pi/7 ?
The answer to area 4cos(7x),4-4cos(7x),0, pi/7 is (4pi+24sqrt(3))/(21)