What is the tangent of y=(x^3-16x)^{14},(4,0) ?

The tangent of y=(x^3-16x)^{14},(4,0) is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=(x^3-16x)^{14},(4,0)

tangent of

y = (x^{3} - 16 x)^{14}, (4, 0)

y = 0

Solution steps

Find the slope of

y = (x^{3} - 16 x)^{14} : \frac{d y}{d x} = 14 (x^{3} - 16 x)^{13} (3 x^{2} - 16)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(4, 0) : y = 0

y = 0

\frac{1}{3 ( 5 - x ^{3} ) ^{5}}

y^{^{'}} + 4 x y = x^{3} e^{x^{2}}, y (0) = - 1

\int x cosh (2 x^{2} - 3) d x

\frac{e ^{- s}}{( s + 1 ) ^{2} + 1}

\int_{0}^{π} 2 sin^{4} (x) d x

What is the tangent of y=(x^3-16x)^{14},(4,0) ?
The tangent of y=(x^3-16x)^{14},(4,0) is y=0