What is the solution for x^2y^{''}-7xy^'-20y=0 ?

The solution for x^2y^{''}-7xy^'-20y=0 is y=c_{1}x^{10}+(c_{2})/(x^2)

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x^2y^{''}-7xy^'-20y=0

x^{2} y^{^{''}} - 7 x y^{^{'}} - 20 y = 0

y = c_{1} x^{10} + \frac{c _{2}}{x ^{2}}

Solution steps

x^{2} y^{''} (x) - 7 x y^{'} (x) - 20 y = 0

Solve linear ODE:

y = c_{1} x^{10} + \frac{c _{2}}{x ^{2}}

y = c_{1} x^{10} + \frac{c _{2}}{x ^{2}}

y^{^{''}} + 9 y = 30 sin (t)

f (x) = e^{x} x

y = 8 cos (3 x), y = 8 sin (3 x), (0, \frac{π}{12})

f (x) = \frac{5}{x}, (1, 5)

\frac{d}{d x} ((x^{2} + x^{3})^{4})

What is the solution for x^2y^{''}-7xy^'-20y=0 ?
The solution for x^2y^{''}-7xy^'-20y=0 is y=c_{1}x^{10}+(c_{2})/(x^2)