What is the derivative of e^2+ln(4) ?

The derivative of e^2+ln(4) is 0

What is the first derivative of e^2+ln(4) ?

The first derivative of e^2+ln(4) is 0

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derivative of

e^{2} + ln (4)

0

Solution steps

\frac{d}{d y} (e^{2} + ln (4))

e^{2} + ln (4) = e^{2} + 2 ln (2)

= \frac{d}{d y} (e^{2} + 2 ln (2))

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

x \to 0 - lim (\frac{1}{x})

x \to 2 lim (\frac{x - 2}{4 - x ^{2}})

\frac{\partial}{\partial x} (\frac{x ^{2} - y ^{2}}{2})

\frac{\partial}{\partial x} (\frac{1}{( x + 3 y )})

\frac{d}{d x} (\frac{9}{4 ( 1 + x ) ^{\frac{5}{2}}})

What is the derivative of e^2+ln(4) ?
The derivative of e^2+ln(4) is 0
What is the first derivative of e^2+ln(4) ?
The first derivative of e^2+ln(4) is 0