What is the limit as x approaches 0+of 1/(1+e^{1/x)} ?

The limit as x approaches 0+of 1/(1+e^{1/x)} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 1/(1+e^{1/x)}

x \to 0 + lim (\frac{1}{1 + e ^{\frac{1}{x}}})

0

Solution steps

x \to 0 + lim (\frac{1}{1 + e ^{\frac{1}{x}}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{lim _{x \to 0 +} ( 1 )}{lim _{x \to 0 +} ( 1 + e ^{\frac{1}{x}} )}

x \to 0 + lim (1) = 1

x \to 0 + lim (1 + e^{\frac{1}{x}}) = \infty

= \frac{1}{\infty}

Apply Infinity Property:

\frac{c}{\infty} = 0

= 0

\frac{d}{d z} (y z e^{x z})

f (x) = 1 + 2 x

\int e^{t} cos (2 t) d t

\int \frac{x ^{3 n}}{n !} d x

\frac{1}{s ^{2} + 2 s + 4}

What is the limit as x approaches 0+of 1/(1+e^{1/x)} ?
The limit as x approaches 0+of 1/(1+e^{1/x)} is 0