What is the integral of sec^2(x)e^{tan(x)} ?

The integral of sec^2(x)e^{tan(x)} is e^{tan(x)}+C

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integral of sec^2(x)e^{tan(x)}

\int sec^{2} (x) e^{t a n (x)} d x

e^{t a n (x)} + C

Solution steps

\int sec^{2} (x) e^{t a n (x)} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = tan (x)

= e^{t a n (x)}

Add a constant to the solution

= e^{t a n (x)} + C

f (x) = x^{π}

x \to 1 - lim (tan (\frac{π x}{2}))

x \to - 6 - lim (\frac{x}{2 x - 12})

y = \frac{8 x ^{w (y, x)} - 5}{3 x ^{3} + 7}

\int_{0}^{1} (x^{2} + 9) e^{- x} d x

What is the integral of sec^2(x)e^{tan(x)} ?
The integral of sec^2(x)e^{tan(x)} is e^{tan(x)}+C