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Popular >

5yln(x)-xy^'=0

Solution

5 y ln (x) - x y^{^{'}} = 0

Solution

y = e^{\frac{5}{2} l n^{2} (x) + c_{1}}

Solution steps

5 y ln (x) - x y^{'} (x) = 0

Solve separable ODE:

y = e^{\frac{5}{2} l n^{2} (x) + c_{1}}

y = e^{\frac{5}{2} l n^{2} (x) + c_{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for 5yln(x)-xy^'=0 ?
The solution for 5yln(x)-xy^'=0 is y=e^{5/2 ln^2(x)+c_{1}}