What is (\partial}{\partial x}(\frac{y-3x)/z) ?

The answer to (\partial}{\partial x}(\frac{y-3x)/z) is -3/z

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(\partial}{\partial x}(\frac{y-3x)/z)

\frac{\partial}{\partial x} (\frac{y - 3 x}{z})

- \frac{3}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{y - 3 x}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (y - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (3 x))

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (3 x) = 3

= \frac{1}{z} (0 - 3)

Simplify

\frac{1}{z} (0 - 3) : - \frac{3}{z}

= - \frac{3}{z}

x y^{^{'}} - y = x^{2} e^{- 3 x}

x \to 1 - lim (2 x + 3)

\int e^{t} 2 t d t

x \to 1 lim (\frac{4 - 4 x}{x - 1})

\int x^{2} (x + \frac{2}{x}) d x

What is (\partial}{\partial x}(\frac{y-3x)/z) ?
The answer to (\partial}{\partial x}(\frac{y-3x)/z) is -3/z