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Popular >

y^'=e^{2x+y}

Solution

y^{^{'}} = e^{2 x + y}

Solution

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Solution steps

y^{'} (x) = e^{2 x + y}

Solve separable ODE:

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Graph

Popular Examples

integral of 5/(5+e^x)

\int \frac{5}{5 + e ^{x}} d x

(\partial)/(\partial x)(ln(1-e^{-x}))

\frac{\partial}{\partial x} (ln (1 - e^{- x}))

derivative of arctan(x/a)

\frac{d}{d x} (arctan (\frac{x}{a}))

(\partial)/(\partial y)(e^{2x}*sin(y))

\frac{\partial}{\partial y} (e^{2 x} \cdot sin (y))

derivative of y=(x^3)/((x-1)^2)derivative of

y = \frac{x ^{3}}{( x - 1 ) ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x+y} ?
The solution for y^'=e^{2x+y} is y=-ln(-1/2 e^{2x}-c_{1})