What is the limit as x approaches 0+of-ln(x) ?

The limit as x approaches 0+of-ln(x) is infinity

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limit as x approaches 0+of-ln(x)

x \to 0 + lim (- ln (x))

\infty

Solution steps

x \to 0 + lim (- ln (x))

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to 0 + lim (ln (x))

Apply the common limit:

x \to 0 + lim (ln (x)) = - \infty

= - (- \infty)

Simplify

= \infty

\int \frac{y ^{2} + 1}{y + 1} d y

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + 1})

x 8 - x^{2}

\int \frac{1}{( 4 + x ^{2} ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (x^{4} + x y^{3})

What is the limit as x approaches 0+of-ln(x) ?
The limit as x approaches 0+of-ln(x) is infinity