What is laplacetransform-3(t-1) ?

The answer to laplacetransform-3(t-1) is -3/(s^2)+3/s

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laplacetransform-3(t-1)

laplace transform

- 3 (t - 1)

- \frac{3}{s ^{2}} + \frac{3}{s}

Solution steps

L {- 3 (t - 1)}

Expand

- 3 (t - 1) : - 3 t + 3

= L {- 3 t + 3}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= - 3 L {t} + L {3}

L {t} : \frac{1}{s ^{2}}

L {3} : \frac{3}{s}

= - 3 \cdot \frac{1}{s ^{2}} + \frac{3}{s}

Refine

- 3 \frac{1}{s ^{2}} + \frac{3}{s} : - \frac{3}{s ^{2}} + \frac{3}{s}

= - \frac{3}{s ^{2}} + \frac{3}{s}

y^{^{'}} = - 4 y + 57

e^{x} d x - y d y = 0, y (0) = 1

\int_{1}^{3} \frac{4}{x ^{2} + 1} d x

\int_{- 2}^{2} 4 (4 - x^{2}) d x

\frac{d ^{2}}{d x ^{2}} (\frac{x}{x ^{2} - 9})

What is laplacetransform-3(t-1) ?
The answer to laplacetransform-3(t-1) is -3/(s^2)+3/s