What is the solution for (y-x)dx+4xdy=0 ?

The solution for (y-x)dx+4xdy=0 is y= x/5+(c_{1})/(\sqrt[4]{x)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(y-x)dx+4xdy=0

(y - x) d x + 4 x d y = 0

y = \frac{x}{5} + \frac{c _{1}}{4 x}

Solution steps

(y - x) d x + 4 x d y = 0

Solve linear ODE:

y = \frac{x}{5} + \frac{c _{1}}{4 x}

y = \frac{x}{5} + \frac{c _{1}}{4 x}

\int \frac{1}{2 x - 1} d x

ln ∣ sin (x) ∣

\int x^{4} (2 x^{5} - 5)^{4} d x

\frac{d}{d x} (\frac{x}{x ^{2} - 1})

\int ln (\frac{2}{x}) d x

What is the solution for (y-x)dx+4xdy=0 ?
The solution for (y-x)dx+4xdy=0 is y= x/5+(c_{1})/(\sqrt[4]{x)}