What is the tangent of sqrt(9-6x) ?

The tangent of sqrt(9-6x) is y=-3/(sqrt(9-6a_{0))}x+sqrt(9-6a_{0)}+(3a_{0})/(sqrt(9-6a_{0))}

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tangent of sqrt(9-6x)

tangent of

9 - 6 x

y = - \frac{3}{9 - 6 a _{0}} x + 9 - 6 a_{0} + \frac{3 a _{0}}{9 - 6 a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 9 - 6 a_{0})

Find the slope of

y = 9 - 6 x : \frac{d y}{d x} = - \frac{3}{9 - 6 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{9 - 6 a _{0}}

Find the line with slope m=

- \frac{3}{9 - 6 a _{0}}

and passing through

(a_{0}, 9 - 6 a_{0}) : y = - \frac{3}{9 - 6 a _{0}} x + 9 - 6 a_{0} + \frac{3 a _{0}}{9 - 6 a _{0}}

y = - \frac{3}{9 - 6 a _{0}} x + 9 - 6 a_{0} + \frac{3 a _{0}}{9 - 6 a _{0}}

\frac{d}{d x} (ln (x + y) - ln (x - y))

\frac{\partial}{\partial x} (cos (x) - x cos (y))

\int 5 t^{2} + e^{0.39 t} + 2 d t

\int \frac{t}{a + b t ^{2}} d t

\int 9 e^{- 9 x} d x

What is the tangent of sqrt(9-6x) ?
The tangent of sqrt(9-6x) is y=-3/(sqrt(9-6a_{0))}x+sqrt(9-6a_{0)}+(3a_{0})/(sqrt(9-6a_{0))}