What is the tangent of g(x)=ln(x^2),(e,2) ?

The tangent of g(x)=ln(x^2),(e,2) is y= 2/e x

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tangent of g(x)=ln(x^2),(e,2)

tangent of

g (x) = ln (x^{2}), (e, 2)

y = \frac{2}{e} x

Solution steps

Find the slope of

g (x) = ln (x^{2}) : \frac{d g ( x )}{d x} = \frac{2}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{e}

Find the line with slope m=

\frac{2}{e}

and passing through

(e, 2) : y = \frac{2}{e} x

y = \frac{2}{e} x

\int_{0}^{8} t + 2 t^{3} d t

(8.2) (- 10.4)

\int \frac{x + 2}{x ^{2} - 4 x} d x

\frac{\partial}{\partial y} (x^{3} + y^{2} - y x^{2} - x y)

x \to 1 - lim ((x - 1) ∣ x - 1 ∣)

What is the tangent of g(x)=ln(x^2),(e,2) ?
The tangent of g(x)=ln(x^2),(e,2) is y= 2/e x