What is the integral from 1 to 16 of sqrt(x) ?

The integral from 1 to 16 of sqrt(x) is 42

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integral from 1 to 16 of sqrt(x)

\int_{1}^{16} x d x

42

Solution steps

\int_{1}^{16} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{16}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{16}

Compute the boundaries:

42

= 42

\frac{s}{s + 1.3}

\frac{\partial}{\partial x} (x y + \frac{x}{y})

f (z) = e^{\frac{z}{z - 1}}

\frac{d}{d x} (5 (x^{3} - 4 x)^{- 3})

\int_{0}^{3} \frac{8 t}{( t - 4 ) ^{2}} d t

What is the integral from 1 to 16 of sqrt(x) ?
The integral from 1 to 16 of sqrt(x) is 42