What is the derivative of ln(8-9x) ?

The derivative of ln(8-9x) is -9/(8-9x)

What is the first derivative of ln(8-9x) ?

The first derivative of ln(8-9x) is -9/(8-9x)

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\frac{d}{d x} (ln (8 - 9 x))

- \frac{9}{8 - 9 x}

Solution steps

\frac{d}{d x} (ln (8 - 9 x))

Apply the chain rule:

\frac{1}{8 - 9 x} \frac{d}{d x} (8 - 9 x)

= \frac{1}{8 - 9 x} \frac{d}{d x} (8 - 9 x)

\frac{d}{d x} (8 - 9 x) = - 9

= \frac{1}{8 - 9 x} (- 9)

Simplify

\frac{1}{8 - 9 x} (- 9) : - \frac{9}{8 - 9 x}

= - \frac{9}{8 - 9 x}

y^{^{''}} + 4 y = t sin (2 t)

\frac{d y}{d x} + 12 y = 7

\frac{\partial}{\partial x} (\frac{x}{y} + \frac{y}{z})

\int 3 x 3 - 3 x d x

\frac{d y}{d x} = \frac{2 x}{3 y ^{2}}

What is the derivative of ln(8-9x) ?
The derivative of ln(8-9x) is -9/(8-9x)
What is the first derivative of ln(8-9x) ?
The first derivative of ln(8-9x) is -9/(8-9x)