What is the integral of (x^5-2x^3) ?

The integral of (x^5-2x^3) is (x^6)/6-(x^4)/2+C

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integral of (x^5-2x^3)

\int (x^{5} - 2 x^{3}) d x

\frac{x ^{6}}{6} - \frac{x ^{4}}{2} + C

Solution steps

\int x^{5} - 2 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{5} d x - \int 2 x^{3} d x

\int x^{5} d x = \frac{x ^{6}}{6}

\int 2 x^{3} d x = \frac{x ^{4}}{2}

= \frac{x ^{6}}{6} - \frac{x ^{4}}{2}

Add a constant to the solution

= \frac{x ^{6}}{6} - \frac{x ^{4}}{2} + C

y = lo g_{2} (x^{2} - 5 x)

\frac{d}{d x} (arctan (\frac{x}{6}))

\int x ln (8 x) d x

y^{'} = 0.0016 y (2500 - y)

y^{^{'}} - y = 6 t e^{2 t}

What is the integral of (x^5-2x^3) ?
The integral of (x^5-2x^3) is (x^6)/6-(x^4)/2+C