What is the integral from-infinity to 1 of 1/(x^2) ?

The integral from-infinity to 1 of 1/(x^2) is diverges

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integral from-infinity to 1 of 1/(x^2)

\int_{- \infty}^{1} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{- \infty}^{1} \frac{1}{x ^{2}} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 0

= \int_{- \infty}^{0} \frac{1}{x ^{2}} d x + \int_{0}^{1} \frac{1}{x ^{2}} d x

\int_{- \infty}^{0} \frac{1}{x ^{2}} d x =

diverges

= diverges

\int_{0}^{6} π (- x^{2} + 6 x) d x

y^{^{'''}} = 4 t^{3} + t

\frac{1}{1 + e ^{- t}}

\int yz e^{y} + 2 y d y

x \to 0 lim (\frac{1 - cos ( 3 x )}{x})

What is the integral from-infinity to 1 of 1/(x^2) ?
The integral from-infinity to 1 of 1/(x^2) is diverges