What is the solution for 2y^{''}+33y=0 ?

The solution for 2y^{''}+33y=0 is y=c_{1}cos(sqrt(33/2)t)+c_{2}sin(sqrt(33/2)t)

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2y^{''}+33y=0

2 y^{^{''}} + 33 y = 0

y = c_{1} cos (\frac{33}{2} t) + c_{2} sin (\frac{33}{2} t)

Solution steps

2 y^{''} (t) + 33 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{33}{2} t) + c_{2} sin (\frac{33}{2} t)

y = c_{1} cos (\frac{33}{2} t) + c_{2} sin (\frac{33}{2} t)

x \to 1 lim (3 x)

k = 1 \sum \infty \frac{( - 1 ) ^{k}}{k}

\frac{d}{d x} ((6 x + 5)^{1.5})

\int_{- 1}^{3} (3 x^{2} - 2 x + 1) d x

\frac{3}{s ^{2} - 1}

What is the solution for 2y^{''}+33y=0 ?
The solution for 2y^{''}+33y=0 is y=c_{1}cos(sqrt(33/2)t)+c_{2}sin(sqrt(33/2)t)