What is (\partial)/(\partial x)((x^3)/(1-x^2)) ?

The answer to (\partial)/(\partial x)((x^3)/(1-x^2)) is (3x^2-x^4)/((1-x^2)^2)

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(\partial)/(\partial x)((x^3)/(1-x^2))

\frac{\partial}{\partial x} (\frac{x ^{3}}{1 - x ^{2}})

\frac{3 x ^{2} - x ^{4}}{( 1 - x ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{3}}{1 - x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial x} ( x ^{3} ) ( 1 - x ^{2} ) - \frac{\partial}{\partial x} ( 1 - x ^{2} ) x ^{3}}{( 1 - x ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (1 - x^{2}) = - 2 x

= \frac{3 x ^{2} ( 1 - x ^{2} ) - ( - 2 x ) x ^{3}}{( 1 - x ^{2} ) ^{2}}

Simplify

\frac{3 x ^{2} ( 1 - x ^{2} ) - ( - 2 x ) x ^{3}}{( 1 - x ^{2} ) ^{2}} : \frac{3 x ^{2} - x ^{4}}{( 1 - x ^{2} ) ^{2}}

= \frac{3 x ^{2} - x ^{4}}{( 1 - x ^{2} ) ^{2}}

\int_{- π}^{π} sin (x) cos (n x) d x

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\int \frac{1}{e ^{x}} d x

\frac{d x}{d t} = 2 x

What is (\partial)/(\partial x)((x^3)/(1-x^2)) ?
The answer to (\partial)/(\partial x)((x^3)/(1-x^2)) is (3x^2-x^4)/((1-x^2)^2)