What is the integral from-2 to 2 of 5-sqrt(4-x^2) ?

The integral from-2 to 2 of 5-sqrt(4-x^2) is 20-2pi

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integral from-2 to 2 of 5-sqrt(4-x^2)

\int_{- 2}^{2} 5 - 4 - x^{2} d x

20 - 2 π

Decimal

13.71681 \dots

Solution steps

\int_{- 2}^{2} 5 - 4 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{2} 5 d x - \int_{- 2}^{2} 4 - x^{2} d x

\int_{- 2}^{2} 5 d x = 20

\int_{- 2}^{2} 4 - x^{2} d x = 2 π

= 20 - 2 π

\int \frac{- 1}{x + 1} d x

f (x) = x^{2} - 2 x - 3

\frac{\partial}{\partial x} (x^{2} e^{x + y} + 2 y cos (x y) - x y^{2} sin (x y))

x^{2}, \frac{2}{( x ^{2} + 1 )}

\frac{\partial}{\partial x} (cos (x + 7 y))

What is the integral from-2 to 2 of 5-sqrt(4-x^2) ?
The integral from-2 to 2 of 5-sqrt(4-x^2) is 20-2pi