What is (d^2)/(dx^2)((5x^2-4x)cos(x)) ?

The answer to (d^2)/(dx^2)((5x^2-4x)cos(x)) is -5x^2cos(x)-20xsin(x)+4xcos(x)+8sin(x)+10cos(x)

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(d^2)/(dx^2)((5x^2-4x)cos(x))

\frac{d ^{2}}{d x ^{2}} ((5 x^{2} - 4 x) cos (x))

- 5 x^{2} cos (x) - 20 x sin (x) + 4 x cos (x) + 8 sin (x) + 10 cos (x)

Solution steps

\frac{d ^{2}}{d x ^{2}} ((5 x^{2} - 4 x) cos (x))

\frac{d}{d x} ((5 x^{2} - 4 x) cos (x)) = cos (x) (10 x - 4) - sin (x) (5 x^{2} - 4 x)

= \frac{d}{d x} (cos (x) (10 x - 4) - sin (x) (5 x^{2} - 4 x))

\frac{d}{d x} (cos (x) (10 x - 4) - sin (x) (5 x^{2} - 4 x)) = - 5 x^{2} cos (x) - 20 x sin (x) + 4 x cos (x) + 8 sin (x) + 10 cos (x)

= - 5 x^{2} cos (x) - 20 x sin (x) + 4 x cos (x) + 8 sin (x) + 10 cos (x)

f (x) = \frac{x - ln ( 1 + x )}{x ^{2}}

2 e^{- \frac{x}{2}} + e^{- x}

x \to + \frac{π}{2} + lim (e^{s e c (x)})

\frac{d}{d x} (\frac{4 x ^{2} + 2 x + 6}{x})

\int \frac{( ln ( x ) ) ^{40}}{x} d x

What is (d^2)/(dx^2)((5x^2-4x)cos(x)) ?
The answer to (d^2)/(dx^2)((5x^2-4x)cos(x)) is -5x^2cos(x)-20xsin(x)+4xcos(x)+8sin(x)+10cos(x)