What is the solution for (dy)/(dx)+3x^2y=x^2 ?

The solution for (dy)/(dx)+3x^2y=x^2 is y=(e^{-x^3+c_{1}})/3+1/3

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(dy)/(dx)+3x^2y=x^2

\frac{d y}{d x} + 3 x^{2} y = x^{2}

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

Solution steps

\frac{d y}{d x} + 3 x^{2} y = x^{2}

Solve separable ODE:

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

y = \frac{e ^{- x^{3} + c_{1}}}{3} + \frac{1}{3}

x \to 0 lim (\frac{cos ( x )}{2})

\int s d s

\frac{d}{d x} ((x + \frac{1}{x}) (5 x^{2} - \frac{1}{x ^{2}}))

f (x) = - 3 3 x \cdot sec (2 x)

\frac{9 x - 9}{- x + 7}

What is the solution for (dy)/(dx)+3x^2y=x^2 ?
The solution for (dy)/(dx)+3x^2y=x^2 is y=(e^{-x^3+c_{1}})/3+1/3