What is the derivative of 7e^{-4x} ?

The derivative of 7e^{-4x} is -28e^{-4x}

What is the first derivative of 7e^{-4x} ?

The first derivative of 7e^{-4x} is -28e^{-4x}

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derivative of

7 e^{- 4 x}

- 28 e^{- 4 x}

Solution steps

\frac{d}{d x} (7 e^{- 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (e^{- 4 x})

Apply the chain rule:

e^{- 4 x} \frac{d}{d x} (- 4 x)

= e^{- 4 x} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= 7 e^{- 4 x} (- 4)

Simplify

= - 28 e^{- 4 x}

\int - 0.6 x^{2} + 80 d x

\int θ sec^{2} (θ) d θ

1 + 2 x

\int \frac{1}{t ^{2} - 1} d t

\frac{d}{d x} (x^{2} + \frac{y ^{2}}{9}) = 1

What is the derivative of 7e^{-4x} ?
The derivative of 7e^{-4x} is -28e^{-4x}
What is the first derivative of 7e^{-4x} ?
The first derivative of 7e^{-4x} is -28e^{-4x}