What is the derivative of sin^2(pi-x) ?

The derivative of sin^2(pi-x) is sin(2x)

What is the first derivative of sin^2(pi-x) ?

The first derivative of sin^2(pi-x) is sin(2x)

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\frac{d}{d x} (sin^{2} (π - x))

sin (2 x)

Solution steps

\frac{d}{d x} (sin^{2} (π - x))

Simplify

sin^{2} (π - x) : sin^{2} (x)

= \frac{d}{d x} (sin^{2} (x))

Apply the chain rule:

2 sin (x) \frac{d}{d x} (sin (x))

= 2 sin (x) \frac{d}{d x} (sin (x))

\frac{d}{d x} (sin (x)) = cos (x)

= 2 sin (x) cos (x)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 x)

\int \frac{a x}{x ^{2} - b x} d x

\frac{d y}{d t} = \frac{3 t ^{2} + t e ^{- t} + 1}{2 y - 4}

\int \frac{a}{x ^{2}} d x

\int \frac{1}{( x + 3 )} d x

\frac{d}{d x} (\frac{( 3 - 2 x - x ^{2} )}{( x ^{2} - 1 )})

What is the derivative of sin^2(pi-x) ?
The derivative of sin^2(pi-x) is sin(2x)
What is the first derivative of sin^2(pi-x) ?
The first derivative of sin^2(pi-x) is sin(2x)