What is the derivative of sqrt(3x^2-4) ?

The derivative of sqrt(3x^2-4) is (3x)/(sqrt(3x^2-4))

What is the first derivative of sqrt(3x^2-4) ?

The first derivative of sqrt(3x^2-4) is (3x)/(sqrt(3x^2-4))

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\frac{d}{d x} (3 x^{2} - 4)

\frac{3 x}{3 x ^{2} - 4}

Solution steps

\frac{d}{d x} (3 x^{2} - 4)

Apply the chain rule:

\frac{1}{2 3 x ^{2} - 4} \frac{d}{d x} (3 x^{2} - 4)

= \frac{1}{2 3 x ^{2} - 4} \frac{d}{d x} (3 x^{2} - 4)

\frac{d}{d x} (3 x^{2} - 4) = 6 x

= \frac{1}{2 3 x ^{2} - 4} \cdot 6 x

Simplify

\frac{1}{2 3 x ^{2} - 4} \cdot 6 x : \frac{3 x}{3 x ^{2} - 4}

= \frac{3 x}{3 x ^{2} - 4}

\int - \frac{2}{3} (1 - x)^{\frac{3}{2}} (1) d x

y^{^{''}} + 25 y = sec (5 x)

\int p d p

\frac{d ^{2} y}{d x ^{2}} - 4 \frac{d y}{d x} + 68 y = 0

x \to - 7 - lim (\frac{- 9 x}{x + 7})

What is the derivative of sqrt(3x^2-4) ?
The derivative of sqrt(3x^2-4) is (3x)/(sqrt(3x^2-4))
What is the first derivative of sqrt(3x^2-4) ?
The first derivative of sqrt(3x^2-4) is (3x)/(sqrt(3x^2-4))