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Popular >

integral of 1/(4+t)

Solution

\int \frac{1}{4 + t} d t

Solution

ln ∣ 4 + t ∣ + C

Solution steps

\int \frac{1}{4 + t} d t

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 4 + t

= ln ∣ 4 + t ∣

Add a constant to the solution

= ln ∣ 4 + t ∣ + C

Graph

Popular Examples

integral of xe^{10x}

\int x e^{10 x} d x

limit as x approaches-b of (((x+b)^7+(x+b)^{10}))/(4(x+b))

x \to - b lim \frac{( ( x + b ) ^{7} + ( x + b ) ^{10} )}{4 ( x + b )}

(\partial)/(\partial x)((x+y)^2+(x+1)^2)

\frac{\partial}{\partial x} ((x + y)^{2} + (x + 1)^{2})

integral of 1/2 sin^2(x)

\int \frac{1}{2} sin^{2} (x) d x

(\partial)/(\partial x)(x+y^2)

\frac{\partial}{\partial x} (x + y^{2})

Frequently Asked Questions (FAQ)

What is the integral of 1/(4+t) ?
The integral of 1/(4+t) is ln|4+t|+C