What is the solution for y^{''}+34y=0 ?

The solution for y^{''}+34y=0 is y=c_{1}cos(sqrt(34)t)+c_{2}sin(sqrt(34)t)

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y^{''}+34y=0

y^{^{''}} + 34 y = 0

y = c_{1} cos (34 t) + c_{2} sin (34 t)

Solution steps

y^{''} (t) + 34 y = 0

Solve linear ODE:

y = c_{1} cos (34 t) + c_{2} sin (34 t)

y = c_{1} cos (34 t) + c_{2} sin (34 t)

d x + d y e^{6 x} = 0

f (x) = e^{1}

\int 4 - 4 x^{2} d x

∣ x - 9 ∣, \frac{x}{2}

y^{^{''}} + 5 y^{^{'}} + 4 y = - 13 t e^{5 t}

What is the solution for y^{''}+34y=0 ?
The solution for y^{''}+34y=0 is y=c_{1}cos(sqrt(34)t)+c_{2}sin(sqrt(34)t)