What is the tangent of f(x)=-3cos(x),\at x= 3/4 pi ?

The tangent of f(x)=-3cos(x),\at x= 3/4 pi is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))

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tangent of f(x)=-3cos(x),\at x= 3/4 pi

tangent of

f (x) = - 3 cos (x), at x = \frac{3}{4} π

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, \frac{3}{2})

Find the slope of

f (x) = - 3 cos (x) : \frac{df ( x )}{d x} = 3 sin (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(\frac{3}{4} π, \frac{3}{2}) : y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

y = \frac{3}{2} x + \frac{3}{2} - \frac{9 π}{4 2}

\int_{0}^{1} (\frac{4 t ^{3}}{1 + t ^{4}}) d t

\int \frac{( x ^{2} )}{( 3 + 4 x - 4 x ^{2} ) ^{\frac{3}{2}}} d x

(0, - 3), (2, 0)

\int_{1}^{3} x 3^{(x^{2})} d x

\frac{d y}{d x} = (\frac{2 y + 5}{4 x + 9})^{2}

What is the tangent of f(x)=-3cos(x),\at x= 3/4 pi ?
The tangent of f(x)=-3cos(x),\at x= 3/4 pi is y= 3/(sqrt(2))x+3/(sqrt(2))-(9pi)/(4sqrt(2))