What is (\partial)/(\partial y)(sin(x+y)+(x+y)) ?

The answer to (\partial)/(\partial y)(sin(x+y)+(x+y)) is cos(x+y)+1

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(\partial)/(\partial y)(sin(x+y)+(x+y))

\frac{\partial}{\partial y} (sin (x + y) + (x + y))

cos (x + y) + 1

Solution steps

\frac{\partial}{\partial y} (sin (x + y) + (x + y))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (sin (x + y)) + \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (sin (x + y)) = cos (x + y)

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= cos (x + y) + 0 + 1

Simplify

= cos (x + y) + 1

x^{2} y \frac{d y}{d x} = e^{x}

n = 1 \sum \infty \frac{3}{n}

\int 9 4 - x^{2} d x

(\frac{1}{x ln ( x )})^{^{'}}

\frac{2 x ^{2} + 6 x + 4}{x}

What is (\partial)/(\partial y)(sin(x+y)+(x+y)) ?
The answer to (\partial)/(\partial y)(sin(x+y)+(x+y)) is cos(x+y)+1