What is the derivative of 1/(2x)-8/(5x^4) ?

The derivative of 1/(2x)-8/(5x^4) is -1/(2x^2)+(32)/(5x^5)

What is the first derivative of 1/(2x)-8/(5x^4) ?

The first derivative of 1/(2x)-8/(5x^4) is -1/(2x^2)+(32)/(5x^5)

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derivative of

\frac{1}{2 x} - \frac{8}{5 x ^{4}}

- \frac{1}{2 x ^{2}} + \frac{32}{5 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x} - \frac{8}{5 x ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{2 x}) - \frac{d}{d x} (\frac{8}{5 x ^{4}})

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

\frac{d}{d x} (\frac{8}{5 x ^{4}}) = - \frac{32}{5 x ^{5}}

= - \frac{1}{2 x ^{2}} - (- \frac{32}{5 x ^{5}})

Simplify

= - \frac{1}{2 x ^{2}} + \frac{32}{5 x ^{5}}

\int \frac{lo g _{e} ( x )}{x} d x

f (x) = ln (10 x)

e^{5 x + 5}

x \to - \infty lim (x^{2} - x)

y = \frac{3 x ^{5} + 9}{x ^{3}}

What is the derivative of 1/(2x)-8/(5x^4) ?
The derivative of 1/(2x)-8/(5x^4) is -1/(2x^2)+(32)/(5x^5)
What is the first derivative of 1/(2x)-8/(5x^4) ?
The first derivative of 1/(2x)-8/(5x^4) is -1/(2x^2)+(32)/(5x^5)