What is the solution for (dy)/(dx)+20y=sin(x) ?

The solution for (dy)/(dx)+20y=sin(x) is y=-(cos(x))/(401)+(20sin(x))/(401)+(c_{1})/(e^{20x)}

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(dy)/(dx)+20y=sin(x)

\frac{d y}{d x} + 20 y = sin (x)

y = - \frac{cos ( x )}{401} + \frac{20 sin ( x )}{401} + \frac{c _{1}}{e ^{20 x}}

Solution steps

\frac{d y}{d x} + 20 y = sin (x)

Solve linear ODE:

y = - \frac{cos ( x )}{401} + \frac{20 sin ( x )}{401} + \frac{c _{1}}{e ^{20 x}}

y = - \frac{cos ( x )}{401} + \frac{20 sin ( x )}{401} + \frac{c _{1}}{e ^{20 x}}

\frac{d}{d x} (3 arctan (x))

\frac{d ^{3}}{d x ^{3}} ((x^{2} - 1)^{3})

\int_{0}^{\frac{π}{2}} 15 cos^{5} (x) d x

x \to - 2 + lim (- \frac{1}{x ^{2} - 4})

\frac{d}{d x} (- a x + \frac{d}{x ^{2}})

What is the solution for (dy)/(dx)+20y=sin(x) ?
The solution for (dy)/(dx)+20y=sin(x) is y=-(cos(x))/(401)+(20sin(x))/(401)+(c_{1})/(e^{20x)}