What is the limit as x approaches 3 of (x^2-9)/(x+1) ?

The limit as x approaches 3 of (x^2-9)/(x+1) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3 of (x^2-9)/(x+1)

x \to 3 lim (\frac{x ^{2} - 9}{x + 1})

0

Solution steps

x \to 3 lim (\frac{x ^{2} - 9}{x + 1})

Plug in the value

x = 3

= \frac{3 ^{2} - 9}{3 + 1}

Simplify

= 0

\int 4 cos (6 x) d x

\int - \frac{3 x}{2} d x

\int \frac{2}{x ^{3} + x} d x

\int_{0}^{2} 4 - x^{2} d x

\frac{\partial}{\partial y} (x y^{2})

What is the limit as x approaches 3 of (x^2-9)/(x+1) ?
The limit as x approaches 3 of (x^2-9)/(x+1) is 0