What is the d/(dt)(5t^{-3/5}) ?

The d/(dt)(5t^{-3/5}) is -3/(t^{8/5)}

What is the first d/(dt)(5t^{-3/5}) ?

The first d/(dt)(5t^{-3/5}) is -3/(t^{8/5)}

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\frac{d}{d t} (5 t^{- \frac{3}{5}})

- \frac{3}{t ^{\frac{8}{5}}}

Solution steps

\frac{d}{d t} (5 t^{- \frac{3}{5}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (t^{- \frac{3}{5}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 5 (- \frac{3}{5} t^{- \frac{3}{5} - 1})

Simplify

5 (- \frac{3}{5} t^{- \frac{3}{5} - 1}) : - \frac{3}{t ^{\frac{8}{5}}}

= - \frac{3}{t ^{\frac{8}{5}}}

\int \frac{1}{x + x} d x

\int \frac{( x ^{2} )}{1 + x ^{3}} d x

x \to - 1 lim (3 x^{2} - 2 x - 1)

f (x) = 3 - x^{2} + 2 x

f (x) = 8 x^{2} + 4 x - 6, at x = - 3

What is the d/(dt)(5t^{-3/5}) ?
The d/(dt)(5t^{-3/5}) is -3/(t^{8/5)}
What is the first d/(dt)(5t^{-3/5}) ?
The first d/(dt)(5t^{-3/5}) is -3/(t^{8/5)}