What is taylor 2x^2+2x ?

The answer to taylor 2x^2+2x is 2x+2x^2

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taylor 2x^2+2x

taylor

2 x^{2} + 2 x

2 x + 2 x^{2}

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( 2 x ^{2} + 2 x ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 2 x ^{2} + 2 x ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 2 x ^{2} + 2 x ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{2}{1 !} x + \frac{4}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Refine

= 2 x + 2 x^{2}

f (x) = \frac{x}{x ^{2} + 81}, at x = 0

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x \to 4 lim (\frac{1}{( 4 - x ) ^{2}})

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