What is (\partial)/(\partial x)(2xy-2y) ?

The answer to (\partial)/(\partial x)(2xy-2y) is 2y

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(\partial)/(\partial x)(2xy-2y)

\frac{\partial}{\partial x} (2 x y - 2 y)

2 y

Solution steps

\frac{\partial}{\partial x} (2 x y - 2 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y) - \frac{\partial}{\partial x} (2 y)

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (2 y) = 0

= 2 y - 0

Simplify

= 2 y

\frac{\partial}{\partial y} (\frac{1}{1 + x ^{2} + y ^{2}})

\frac{d}{d x} (x^{2} x^{3} + a^{3})

\int \frac{3 x ^{3} + 3 x + 2}{x ^{3} + x} d x

f (x) = \frac{1}{x ^{4}}, at x = 3

\frac{\partial}{\partial z} (x e^{z})

What is (\partial)/(\partial x)(2xy-2y) ?
The answer to (\partial)/(\partial x)(2xy-2y) is 2y