What is (\partial)/(\partial y)(x*y+y^2) ?

The answer to (\partial)/(\partial y)(x*y+y^2) is x+2y

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(\partial)/(\partial y)(x*y+y^2)

\frac{\partial}{\partial y} (x \cdot y + y^{2})

x + 2 y

Solution steps

\frac{\partial}{\partial y} (x y + y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x y) + \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (y^{2}) = 2 y

= x + 2 y

\int cos (x) - 1 d x

f (x) = 2 x e^{x}, at x = 0

\frac{\partial}{\partial x} (4 ln (x y) + 3 ln (yz) + ln (x z))

x = y^{2} - 4 y, x = y - y^{2}

2 y^{^{''}} - 15 y^{^{'}} - 8 y = 0

What is (\partial)/(\partial y)(x*y+y^2) ?
The answer to (\partial)/(\partial y)(x*y+y^2) is x+2y