What is the solution for (x^2+4)dy=(2x-8xy)dx ?

The solution for (x^2+4)dy=(2x-8xy)dx is y=(c_{1})/(4(x^8+16x^6+96x^4+256x^2+256))+1/4

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(x^2+4)dy=(2x-8xy)dx

(x^{2} + 4) d y = (2 x - 8 x y) d x

y = \frac{c _{1}}{4 ( x ^{8} + 16 x ^{6} + 96 x ^{4} + 256 x ^{2} + 256 )} + \frac{1}{4}

Solution steps

(x^{2} + 4) d y = (2 x - 8 x y) d x

Solve separable ODE:

y = \frac{c _{1}}{4 ( x ^{8} + 16 x ^{6} + 96 x ^{4} + 256 x ^{2} + 256 )} + \frac{1}{4}

y = \frac{c _{1}}{4 ( x ^{8} + 16 x ^{6} + 96 x ^{4} + 256 x ^{2} + 256 )} + \frac{1}{4}

\int - \frac{2}{πn} cos (\frac{πn}{2} x) d x

\frac{d y}{d x} = \frac{7 x ^{2}}{5 y ^{2}}

f (x) = (\frac{( x + 1 )}{( x - 1 )})^{2}

\int 7 tan^{2} (x) sec (x) d x

x \to 0 lim (\frac{2}{1 + 2 ^{\frac{1}{x}}})

What is the solution for (x^2+4)dy=(2x-8xy)dx ?
The solution for (x^2+4)dy=(2x-8xy)dx is y=(c_{1})/(4(x^8+16x^6+96x^4+256x^2+256))+1/4