What is the derivative of 5x^2cos(x+x) ?

The derivative of 5x^2cos(x+x) is 5(2xcos(x)-x^2sin(x))+1

What is the first derivative of 5x^2cos(x+x) ?

The first derivative of 5x^2cos(x+x) is 5(2xcos(x)-x^2sin(x))+1

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\frac{d}{d x} (5 x^{2} cos (x) + x)

5 (2 x cos (x) - x^{2} sin (x)) + 1

Solution steps

\frac{d}{d x} (5 x^{2} cos (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{2} cos (x)) + \frac{d x}{d x}

\frac{d}{d x} (5 x^{2} cos (x)) = 5 (2 x cos (x) - x^{2} sin (x))

\frac{d x}{d x} = 1

= 5 (2 x cos (x) - x^{2} sin (x)) + 1

\frac{\partial}{\partial y} (\frac{( y + x )}{( y - x )})

f (x) = x^{2} - 2

2 \frac{d y}{d x} = x y (x + 1)

\int x (2 x + 7)^{8} d x

\int \frac{1}{x ( 2 - x )} d x

What is the derivative of 5x^2cos(x+x) ?
The derivative of 5x^2cos(x+x) is 5(2xcos(x)-x^2sin(x))+1
What is the first derivative of 5x^2cos(x+x) ?
The first derivative of 5x^2cos(x+x) is 5(2xcos(x)-x^2sin(x))+1