What is inverse oflaplace {1/(4s+1)} ?

The answer to inverse oflaplace {1/(4s+1)} is 1/4 e^{-t/4}

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inverse oflaplace {1/(4s+1)}

inverse laplace

{\frac{1}{4 s + 1}}

\frac{1}{4} e^{- \frac{t}{4}}

Solution steps

L^{- 1} {\frac{1}{4 s + 1}}

= L^{- 1} {\frac{1}{4} \cdot \frac{1}{s + \frac{1}{4}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{1}{4} L^{- 1} {\frac{1}{s + \frac{1}{4}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + \frac{1}{4}}} = e^{- \frac{t}{4}}

= \frac{1}{4} e^{- \frac{t}{4}}

\int (5 sec (x) - cos (x))^{2} d x

\int cot^{3} (4 x) sec^{2} (4 x) d x

\int (4 - x^{2}) d x

x \to 0 - lim (\frac{e ^{x}}{x ^{3}})

\frac{y}{4}

What is inverse oflaplace {1/(4s+1)} ?
The answer to inverse oflaplace {1/(4s+1)} is 1/4 e^{-t/4}