What is the derivative of sin(3x^2-1) ?

The derivative of sin(3x^2-1) is cos(3x^2-1)*6x

What is the first derivative of sin(3x^2-1) ?

The first derivative of sin(3x^2-1) is cos(3x^2-1)*6x

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\frac{d}{d x} (sin (3 x^{2} - 1))

cos (3 x^{2} - 1) \cdot 6 x

Solution steps

\frac{d}{d x} (sin (3 x^{2} - 1))

Apply the chain rule:

cos (3 x^{2} - 1) \frac{d}{d x} (3 x^{2} - 1)

= cos (3 x^{2} - 1) \frac{d}{d x} (3 x^{2} - 1)

\frac{d}{d x} (3 x^{2} - 1) = 6 x

= cos (3 x^{2} - 1) \cdot 6 x

x \to 0 lim ((1 + x)^{\frac{1}{3 x}})

y = 3 x + 3 x

\frac{d y}{d x} + y = e^{x} y^{- 2}

y = x^{3}, at x = - 4

\int_{- 4}^{0} (4 + 16 - x^{2}) d x

What is the derivative of sin(3x^2-1) ?
The derivative of sin(3x^2-1) is cos(3x^2-1)*6x
What is the first derivative of sin(3x^2-1) ?
The first derivative of sin(3x^2-1) is cos(3x^2-1)*6x