What is the integral of e^{-x/(100)} ?

The integral of e^{-x/(100)} is -100e^{-x/(100)}+C

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integral of e^{-x/(100)}

\int e^{- \frac{x}{100}} d x

- 100 e^{- \frac{x}{100}} + C

Solution steps

\int e^{- \frac{x}{100}} d x

Apply u-substitution

: \int - 100 e^{u} d u

= \int - 100 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 100 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 100 e^{u}

Substitute back

u = - \frac{x}{100}

= - 100 e^{- \frac{x}{100}}

Add a constant to the solution

= - 100 e^{- \frac{x}{100}} + C

\int 15 x^{2} e^{5 x^{3} - 6} d x

s \to 0 lim (\frac{- \frac{1}{s}}{1 + ( 3 + \frac{13}{s} ) ( \frac{7}{x s + 1} )})

x \to 1 + lim (\frac{3}{∣ x - 1 ∣})

x^{3}

\frac{\partial}{\partial x} (\frac{x ^{2}}{x ^{2} + y ^{2}})

What is the integral of e^{-x/(100)} ?
The integral of e^{-x/(100)} is -100e^{-x/(100)}+C