What is the limit as x approaches 3+of ln|x^2-9| ?

The limit as x approaches 3+of ln|x^2-9| is -infinity

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limit as x approaches 3+of ln|x^2-9|

x \to 3 + lim (ln x^{2} - 9)

- \infty

Solution steps

x \to 3 + lim (ln x^{2} - 9)

x^{2} - 9

is positive when

x \to 3 +

. Therefore

x^{2} - 9 = x^{2} - 9

= x \to 3 + lim (ln (x^{2} - 9))

Apply the Limit Chain Rule:

- \infty

= - \infty

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7 x^{2} y + \frac{d y}{d x} = 4 x^{2}

What is the limit as x approaches 3+of ln|x^2-9| ?
The limit as x approaches 3+of ln|x^2-9| is -infinity